Reductive ozonolysis of polymer of 1,3-butadiene will mainly form:

H C H O

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C H O | C H O

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C H_{2} - C H O | C H_{2} - C H O

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C H_{3} - C H O

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Solution

The correct option is A $C H O | C H O$
$H_{2} C = o o = C H - C H = o o = C H_{2}$
i.e. HCHO two moles
$C H O | C H O$ one mole

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