Reemu read 1-5th pages of a book- If she reads further 40 pages- she would have read 7-10th pages of the book- How many pages are left to be read-

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Standard VI

Mathematics

Addition of Fractions

Reemu read ...

Question

Reemu read $\frac{1}{5} t h$ pages of a book. If she reads further 40 pages, she would have read $\frac{7}{10}$ th pages of the book. How many pages are left to be read?

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Solution

First we will assume the pages in the book be x
2/3 of x + 40 = 7/10 of x
2x/3 + 40 = 7x / 10
7x /10 - 2x/3 = 40
21x 20x / 30 = 40
x / 30 = 40
x = 1200
1200 × 7/10 = 840 pages are read
and 1200 - 840 = 360
So this means there are 360 pages left to be read.

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Reemu read 15th pages of a book. If she reads further 40 pages, she would have read 710th pages of the book. How many pages are left to be read?

First we will assume the pages in the book be x2/3 of x + 40 = 7/10 of x2x/3 + 40 = 7x / 107x /10 - 2x/3 = 4021x 20x / 30 = 40x / 30 = 40x = 12001200 × 7/10 = 840 pages are readand 1200 - 840 = 360So this means there are 360 pages left to be read.

Reemu read $\frac{1}{5} t h$ pages of a book. If she reads further 40 pages, she would have read $\frac{7}{10}$ th pages of the book. How many pages are left to be read?

First we will assume the pages in the book be x
2/3 of x + 40 = 7/10 of x
2x/3 + 40 = 7x / 10
7x /10 - 2x/3 = 40
21x 20x / 30 = 40
x / 30 = 40
x = 1200
1200 × 7/10 = 840 pages are read
and 1200 - 840 = 360
So this means there are 360 pages left to be read.