Question 61 Reenu read 1-5 th pages of a book- If she reads further 40 pages- she would have read 7-10 th pages of the book- How many pages are left to be read-

Let the total pages of the book be x. According to the question, 1/5 x +40 = 7/10 x ⇒ 40 = 7/10 x 1/5 x = 7x 2x/10 ⇒ 40 = 5x/10 ⇒ x= 400/5 = 80 ∴ Total pa ...

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Standard X

Mathematics

Method of Substitution to Find the Solution of a Pair of Linear Equations

Question 61 R...

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Question 61

Reenu read $\frac{1}{5} t h$ pages of a book. If she reads further 40 pages, she would have read $\frac{7}{10} t h$ pages of the book. How many pages are left to be read?

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Solution

Let the total pages of the book be x.
According to the question, $\frac{1}{5} x + 40 = \frac{7}{10} x \Rightarrow 40 = \frac{7}{10} x - \frac{1}{5} x = \frac{7 x - 2 x}{10} \Rightarrow 40 = \frac{5 x}{10} \Rightarrow x = \frac{400}{5} = 80$
$∴$ Total pages of a book $= 80$
Hence pages lef to be read = total pages of a book- $(\frac{7}{10} x)$
$= 80 - \frac{7}{10} \times 80$
$= 80 - 56 = 24$ pages

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Method of Substitution to Find the Solution of a Pair of Linear Equations

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Question 61 Reenu read 15th pages of a book. If she reads further 40 pages, she would have read 710th pages of the book. How many pages are left to be read?

Let the total pages of the book be x. According to the question, 15x+40=710x⇒40=710x−15x=7x−2x10⇒40=5x10⇒x=4005=80 ∴ Total pages of a book =80 Hence pages lef to be read = total pages of a book- (710x) =80−710×80 =80−56=24 pages

Question 61

Reenu read $\frac{1}{5} t h$ pages of a book. If she reads further 40 pages, she would have read $\frac{7}{10} t h$ pages of the book. How many pages are left to be read?