Question

Ref. image Half-life is independent of concentration of reactant. After minutes volume of $N_2$ gas is $10L$ and after complete reaction it is $50L$. Hence rate constant is :

• A. $\left(2.303/10\right)\log 5mi{n}^{-1}$
• B. $\left(2.303/10\right)\log 1.25mi{n}^{-1}$
• C. $\left(2.303/10\right)\log 2mi{n}^{-1}$
• D. $\left(2.303/10\right)\log 4mi{n}^{-1}$

Answer 1

The correct option is A $\left(2.303/10\right)\log 5mi{n}^{-1}$

Half Life is independent of concentration of reactant. So Its a 1st Order Reaction.

So,

$k=\frac{2.303}{t}log\frac{\left[V_2\right]}{\left[V_1\right]}$

$k=\frac{2.303}{10}log\frac{50}{10}$

$k=\frac{2.303}{10}log[5]{min}^{-1}$