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Byju's Answer
Standard XII
Chemistry
Activation Energy
Refer diagram...
Question
Refer diagram and Match List-1 with List-2.
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Solution
E
a
(
f
)
=
(
50
−
20
)
K
J
/
m
o
l
E
a
(
f
)
=
30
K
J
m
o
l
−
1
E
a
(
b
)
=
(
50
−
10
)
K
J
/
m
o
l
E
a
(
b
)
=
40
K
J
m
o
l
−
1
△
r
H
=
E
a
(
f
)
−
E
a
(
b
)
=
(
30
−
40
)
K
J
/
m
o
l
=
−
10
K
J
/
m
o
l
Threshold energy
=
50
K
J
/
m
o
l
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