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Equipartition Theorem

Refer to figu...

Question

Refer to figure. Let $△ U_{1}$ and $△ U_{2}$ be the change in internal energy in processes A and B respectively, $△ Q$ be the net heat given to the system in process $(A + B)$ and $△ W$ be the net work done by the system in the process $(A + B)$

A

△ U_{1} + △ U_{2} = 0

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B

△ U_{1} - △ U_{2} = 0

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C

△ Q_{1} - △ W = 0

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D

△ Q_{1} + △ W = 0

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Solution

The correct options are
A $△ U_{1} + △ U_{2} = 0$
C $△ Q_{1} - △ W = 0$

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Similar questions

Q. Refer to figure. Let ∆U₁ and ∆U₂ be the change in internal energy in processes A and B respectively, ∆Q be the net heat given to the system in process A + B and ∆W be the net work done by the system in the process A + B.

(a) ∆U₁ + ∆U₂ = 0.
(b) ∆U₁ − ∆U₂ = 0.
(c) ∆Q − ∆W = 0.
(d) ∆Q + ∆W = 0

Δ U_{1}

Δ U_{2}

be the change in internal energy in process A and B respectively,

Δ Q

be the net heat given to the system in process (A+B) and

Δ W

be the net work done by the system in the process (A+ B).
i)

Δ U_{1} + Δ U_{2} = 0

Δ U_{1} - Δ U_{2} = 0

Δ Q + Δ W = 0

Δ Q + Δ W = 0

Q. Figure shows two processes a and b for a given sample of a gas> If

△ Q_{1}, △ Q_{2}

are the amounts of heat absorbed by the system in the cases and

△ U_{1}, △ U_{2}

are changes in internal energies respectively, then

U_{1}, U_{2}, U_{3}

represents the potential energy of mass

m

moving from A to B along three different paths

1

2

3

(as shown in the figure) in the gravitational field, then

Q. Refer to figure. Let ∆U₁ and ∆U₂ be the changes in internal energy of the system in the process A and B. Then
(a) ∆U₁ > ∆U₂
(b) ∆U₁ = ∆U₂
(c) ∆U₁ < ∆U₂
(d) ∆U₁ ≠ ∆U₂.

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