Refer to the figure above, in which $m_{1}$ and $m_{2}$ are connected via a light cord which passes over a massless pulley. Take $m_{2} > m_{1}$ , such that $m_{2}$ remains on the floor while $m_{1}$ remains suspended.
What is the normal force $F_{N}$ exerted on $m_{2}$ ?

m_{1} g

No worries! We‘ve got your back. Try BYJU‘S free classes today!

m_{2} g

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(m_{2} - m_{1}) g

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

(m_{2} + m_{1}) g

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{m_{2} - m_{1}}{m_{2} + m_{1}} m_{2} g

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $(m_{2} - m_{1}) g$
Let the tension in the string be $T$ .
For block of mass $m_{1}$ : $T - m_{1} g = 0$ $⟹ T = m_{1} g$

For block of mass $m_{2}$ : $T + F_{N} = m_{2} g$
$∴$ $m_{1} g + F_{N} = m_{2} g$ $⟹ F_{N} = (m_{2} - m_{1}) g$

Suggest Corrections

Similar questions

Two bodies of masses m₁ and m₂ are connected by a light, inextensible string, which passes over a frictionless pulley. If the pulley is moving upward with uniform acceleration g, then the tension in the string is

Q. A constant force

F = \frac{m_{2} g}{2}

is applied on the block of mass

m_{1}

as shown in fig. The string and the pulley are light and the surface of the table is smooth. The acceleration of

m_{1}

A hanging body of mass $m_{1}$ is pulled by a force F = $m_{2}$ g acting on the massless inextensible smooth string. The acceleration of $m_{1}$ is:

Two spheres of masses m1 and m2 (m1>m2) respectively are tied to the ends of a light, inextensible string which passes over a light frictionless pulley. When the masses are released from their initial state of rest, the acceleration of their centre of mass is:

Q. A frictionless cart of mass

M

carries two other frictionless carts having masses

m_{1}

and

m_{2}

connected by a string passing over a pulley as shown in figure. The horizontal force that must be applied on

M,

so that

m_{1}

and

m_{2}

do not move relative to it will be

Join BYJU'S Learning Program

Refer to the figure above, in which m1 and m2 are connected via a light cord which passes over a massless pulley. Take m2>m1, such that m2 remains on the floor while m1 remains suspended.What is the normal force FN exerted on m2?

The correct option is C (m2−m1)gLet the tension in the string be T.For block of mass m1 : T−m1g=0 ⟹T=m1gFor block of mass m2 : T+FN=m2g ∴ m1g+FN=m2g ⟹FN=(m2−m1)g

Refer to the figure above, in which $m_{1}$ and $m_{2}$ are connected via a light cord which passes over a massless pulley. Take $m_{2} > m_{1}$ , such that $m_{2}$ remains on the floor while $m_{1}$ remains suspended.
What is the normal force $F_{N}$ exerted on $m_{2}$ ?

The correct option is C $(m_{2} - m_{1}) g$
Let the tension in the string be $T$ .
For block of mass $m_{1}$ : $T - m_{1} g = 0$ $⟹ T = m_{1} g$

For block of mass $m_{2}$ : $T + F_{N} = m_{2} g$
$∴$ $m_{1} g + F_{N} = m_{2} g$ $⟹ F_{N} = (m_{2} - m_{1}) g$