Refer to the following figure:

∠BCA = ∠EFD. Find EF.

$\frac{h^{2}}{d}$

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$\frac{2 h}{d}$

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$\frac{h}{d}$

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$\frac{d^{2}}{h}$

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Solution

The correct option is A
$\frac{h^{2}}{d}$

In ΔABC, tan $φ$ = $\frac{A B}{B C}$ = $\frac{d}{h}$

In ΔDEF, tan $φ$ = $\frac{D E}{E F}$ = $\frac{d}{h}$

So, EF = $\frac{h^{2}}{d}$

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Refer to the following figure: ∠BCA = ∠EFD. Find EF.

The correct option is A h2d In ΔABC, tanφ =ABBC = dh In ΔDEF, tanφ = DEEF = dh So, EF = h2d

Refer to the following figure:

∠BCA = ∠EFD. Find EF.

The correct option is A
$\frac{h^{2}}{d}$

In ΔABC, tan $φ$ = $\frac{A B}{B C}$ = $\frac{d}{h}$

In ΔDEF, tan $φ$ = $\frac{D E}{E F}$ = $\frac{d}{h}$

So, EF = $\frac{h^{2}}{d}$