Refer to the isosceles triangle shown, where AB = AC = x. AE is the perpendicular such that AE = p and BC = d. Find the length of CD ___. (Given that AB⊥CD and also, d = 2x)
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Solution
Area of the triangle ΔABC=12×AE×BC=12×AB×CD ⇒AE×BC=AB×CD ⇒CD=AE×BCAB=pdx,sinced=2x,CD=2p