Question

Referring to the above two questions, the acceleration due to gravity is given by

• A. $10m/se{c}^2$
• B. $5m/se{c}^2$
• C. $20m/se{c}^2$
• D. $2.5m/se{c}^2$

Answer 1

The correct option is A $10m/se{c}^2$

$a_x=\frac{d}{dt}\left(v_x\right)=0,a_y=\frac{d}{dt}\left(v_y\right)=-10m/s^2$
$\therefore Netaccelerationa=\sqrt{a_x^2+a_y^2}=\sqrt{0^2+{10}^2}=10m/s^2$