Question

Referring to the figure, if area of square $1$ is $16$ square units, area of square $2$ is $48$ square units, then the area of square $3$ is

• A. $56$
• B. $64$
• C. $78$
• D. $96$

Answer 1

Answer: (B)

$64$

Since the area of square $1$ is $16$ square units, its side would be $4$ units.

Similarly side of square $2$ would be $\sqrt{48}$ units

The triangle formed in between three squares becomes a right angled triangle since the angle of a square are right angles.

Therefore side of square $3$ can be written as $\sqrt{(4{)}^2+(\sqrt{48}{)}^2}=\sqrt{16+48}=8$ units

Area of square $3$ becomes $64$ square units.