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Question

Reflection of the line ¯¯¯az+a¯¯¯z=0 in the real axis is

A
¯¯¯¯¯¯az+az=0
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B
¯¯¯¯¯aa+ZZ=0
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C
(a+¯¯¯a)(z+¯¯¯z)=0
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D
az =0
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Solution

The correct option is A ¯¯¯¯¯¯az+az=0
Let a=α+iβ z=x+iy
Now,
¯az+a¯z=0
(αiβ)(x+iy)+(α+iβ)(xiy)=0
2(αx+βy)=0αx+βy=0 line passes through origin.
Slope =αxβ
So reflection slope =αβx
line is αxβy=0reflection also passes through origin
(a+¯a2)(z+¯z2)(a¯a2i)(z¯z2i)=0
az+¯a¯z=0
59020_34799_ans_960ce620bf7c4f5a9d66b255bbefa20b.png

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