Refraction takes placed at a concave spherical boundary separating glass-air medium. For the image to be real, the object distance (μg=3/2).
A
Greater than three times the radius of curvature of the refracting surface
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B
Greater than two times the radius of curvature of the refracting surface
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C
Greater than the radius of curvature of the refracting surface
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D
Independent of the radius of curvature of the refracting surface
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Solution
The correct option is B Greater than two times the radius of curvature of the refracting surface The two slabs will shift the image a distance d=2(1−1μ)t=2(1−11.5)(1.5)=1.0cm Therefore, final image will be 1cm above point P.