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Question

# Refractive index of air is μ1=1 (outside medium), refractive index of slab is μ2=1.5, thickness of slab t=6 cm . If the object is placed at 28 cm from nearest surface of slab, find the final image position wrt mirror. ( Assume that mirror is very near to the slab)

A
30 cm behind the mirror.
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B
32 cm behind the mirror.
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C
36 cm behind the mirror.
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D
26 cm behind the mirror.
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Solution

## The correct option is A 30 cm behind the mirror.A ray of light from the object first encounters a glass slab, then a mirror and finally a glass slab again A slab simply shifts the object along the axis by a distance s1=t(1−1μ)=2 cm Direction of shift is towards left. Therefore the object appears to be at I1 which is 28–2=26 cm from the slab. Mirror: The object for the mirror is the image I1 formed after shift due to the slab. Therefore object distance from the mirror is 26+6=32 cm. The image will now be formed 32 cm behind the mirror. Slab: The ray now travels through the slab again but this time from right to left. Therefore it is shifted again by a distance of cm, but towards the right. Thus final position the image is 32–2=30 cm behind the mirror. Conclusion: Final image is formed 30 cm behind the mirror.

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