Refractive indices of four substances W, X, Y, Z are $1.20, 1.77, 1.36, 1.50$ respectively. The speed of light will be maximum in:

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Solution

The correct option is A W
Speed of light , $v = \frac{c}{μ}$

where $c$ =speed of light in vacuum
and $μ$ = refractive index of medium

Hence, for maximum speed, $μ$ should be minimum.

Hence, speed of light will be maximum in W having minimum $μ$ .

Answer-(A).

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Refractive indices of four substances W, X, Y, Z are 1.20,1.77,1.36,1.50 respectively. The speed of light will be maximum in:

The correct option is A WSpeed of light ,v=cμ where c=speed of light in vacuum and μ = refractive index of mediumHence, for maximum speed, μ should be minimum.Hence, speed of light will be maximum in W having minimum μ.Answer-(A).

Refractive indices of four substances W, X, Y, Z are $1.20, 1.77, 1.36, 1.50$ respectively. The speed of light will be maximum in:

The correct option is A W
Speed of light , $v = \frac{c}{μ}$

where $c$ =speed of light in vacuum
and $μ$ = refractive index of medium

Hence, for maximum speed, $μ$ should be minimum.

Hence, speed of light will be maximum in W having minimum $μ$ .

Answer-(A).