Refractive indices of water and glass are 4/3 and 3/2 respectively. A ray of light travelling in water is incident on the water-glass interface at 30 $^{o}$ . Calculate the angle of refraction.

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Solution

The ray is moving from water to glass , incidence angle is $s i n i = 30^{o}$
Now using the snell's law
$μ_{w a t e r} s i n i = μ_{g l a s s} s i n r$ , $r$ is angle of refraction
$\frac{4}{3} s i n 30 = \frac{3}{2} s i n r$
$s i n r = 0.44$
$r = {26.3}^{0}$

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Refractive indices of water and glass are 4/3 and 3/2 respectively. A ray of light travelling in water is incident on the water-glass interface at 30o. Calculate the angle of refraction.

The ray is moving from water to glass , incidence angle is sini=30oNow using the snell's lawμwatersini=μglasssinr, r is angle of refraction 43sin30=32sinrsinr=0.44r=26.30

Refractive indices of water and glass are 4/3 and 3/2 respectively. A ray of light travelling in water is incident on the water-glass interface at 30 $^{o}$ . Calculate the angle of refraction.

The ray is moving from water to glass , incidence angle is $s i n i = 30^{o}$
Now using the snell's law
$μ_{w a t e r} s i n i = μ_{g l a s s} s i n r$ , $r$ is angle of refraction
$\frac{4}{3} s i n 30 = \frac{3}{2} s i n r$
$s i n r = 0.44$
$r = {26.3}^{0}$