Question

Regarding graphite the following information are available:

The density of graphite = $2.25gm/c{m}^3$. What is c – c bond distance in graphite?

• A. 1.68 A
• B. 1.545 A
• C. 2.852 A
• D. 1.426 A

Answer 1

The correct option is D 1.426 A

Let c – c bond distance in graphite is dA

$\therefore Surfacearea=6\times \frac{\sqrt{3}}{4}\times d^2=6\times \frac{\sqrt{3}}{4}\times d^2\times {10}^{-16}c{m}^2$

$\therefore vol.oftheunitcell=6\times \frac{\sqrt{3}}{4}\times d^2\times {10}^{-16}\times 3.35\times {10}^{-8}c{m}^3$

$\therefore massoftheunitcell=6\times \frac{\sqrt{3}}{4}\times d^2\times 2.25\times {10}^{-24}gm$

$\therefore 6\times \frac{\sqrt{3}}{4}\times 3.35\times 2.25\times {10}^{-24}\times d^2=12\times \frac{10}{6}\times {10}^{-24}\times 2$

$\therefore d^2=\frac{10}{3}\times 4\frac{1\times 2}{\sqrt{3}\times 3.35\times 2.25}=2.04265$

Or d = 1.429 A