Relate the image distance ( $v$ ), object distance ( $u$ ) , image height ( $h^{^{'}}$ ) and object height ( $h$ ) to the formula of magnification $(M)$ for a mirror.

$M = \frac{h}{h^{'}}$ = $\frac{v}{u}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$M = \frac{h^{'}}{h}$ = $\frac{- u}{v}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$M = \frac{h^{'}}{h}$ = $\frac{- v}{u}$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

$M = \frac{h^{'}}{h}$ = $\frac{u}{v}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C
$M = \frac{h^{'}}{h}$ = $\frac{- v}{u}$

$M = \frac{h^{'}}{h}$ = $\frac{- v}{u}$ where h' is the image height, h is the object height, v is the image distance and u is the object distance.

Suggest Corrections

Similar questions

Relate the image distance (v), object distance(u) , image height(h') and object height(h) for the formula of magnification (M).

Q. In a lens, if

u

- distance of object from lens

v

- distance of image from lens

h_{i}

- height of image

h_{o}

- height of object. Compare the following quanties.

A	B
$\frac{h_{i}}{h_{o}}$	$\frac{v}{u}$

Q. An object

5 c m

of height is placed at the distance of

25 c m

in front of convex lens of focal length

10 c m

. Determine the size (h'), magnification (m) and position of image (v) with proper signs? Assume object distance to be negative and object height to be positive.

In a lens, if
$u$ - distance of the object from the lens
$v$ - distance of the image from the lens
$h_{i}$ - height of the image
$h$ - height of the object,

then determine the relationship between the two quantities, Quantity A and Quantity B.

Q. Calculate distance of an object from height

^{'} h^{'}

of a concave mirror of focal length

= 10

so as to obtain real image of magnification.

m = - 2, v = 2 u

Join BYJU'S Learning Program

Relate the image distance (v), object distance (u) , image height (h′) and object height (h) to the formula of magnification (M) for a mirror.

The correct option is C M=h′h = −vu M=h′h = −vu where h' is the image height, h is the object height, v is the image distance and u is the object distance.

Relate the image distance ( $v$ ), object distance ( $u$ ) , image height ( $h^{^{'}}$ ) and object height ( $h$ ) to the formula of magnification $(M)$ for a mirror.

The correct option is C
$M = \frac{h^{'}}{h}$ = $\frac{- v}{u}$

$M = \frac{h^{'}}{h}$ = $\frac{- v}{u}$ where h' is the image height, h is the object height, v is the image distance and u is the object distance.