Relate the image distance -v- object distance -u- - image height -h- and object height -h- to nbsp-the formula of magnification -M- for a mirror- M - h-h - -u-v-M - h-h - -v-u-M - h-h- - v-u-M - h-h - u-v-

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Standard X

Physics

Magnification of Mirrors

Relate the im...

Question

Relate the image distance ( $v$ ), object distance ( $u$ ) , image height ( $h^{^{'}}$ ) and object height ( $h$ ) to the formula of magnification $(M)$ for a mirror.

$M = \frac{h}{h^{'}}$ = $\frac{v}{u}$

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$M = \frac{h^{'}}{h}$ = $\frac{- u}{v}$

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$M = \frac{h^{'}}{h}$ = $\frac{- v}{u}$

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$M = \frac{h^{'}}{h}$ = $\frac{u}{v}$

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Solution

The correct option is C
$M = \frac{h^{'}}{h}$ = $\frac{- v}{u}$

$M = \frac{h^{'}}{h}$ = $\frac{- v}{u}$ where h' is the image height, h is the object height, v is the image distance and u is the object distance.

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Similar questions

Q. Calculate the Q-values of the following fusion reactions:
(a)

{}_{1}^{2}H + {}_{1}^{2}H \to {}_{1}^{3}H + {}_{1}^{1}H

(b)

{}_{1}^{2}H + {}_{1}^{2}H \to {}_{2}^{3}{He} + n

(c)

{}_{1}^{2}H + {}_{1}^{3}H \to {}_{2}^{4}{He} + n

.
Atomic masses are

m ({}_{1}^{2}H) = 2.014102 u, m ({}_{1}^{3}H) = 3.016049 u, m ({}_{2}^{3}H e) = 3.016029 u, m ({}_{2}^{4}H e) = 4.002603 u .

Relate the image distance ( $v$ ), object distance ( $u$ ) , image height ( $h^{^{'}}$ ) and object height ( $h$ ) to the formula of magnification $(M)$ for a mirror.

Relate the image distance (v), object distance(u) , image height(h') and object height(h) for the formula of magnification (M).

Q. In a lens, if

u

- distance of object from lens

v

- distance of image from lens

h_{i}

- height of image

h_{o}

- height of object. Compare the following quanties.

A	B
$\frac{h_{i}}{h_{o}}$	$\frac{v}{u}$

Q. An object

5 c m

of height is placed at the distance of

25 c m

in front of convex lens of focal length

10 c m

. Determine the size (h'), magnification (m) and position of image (v) with proper signs? Assume object distance to be negative and object height to be positive.

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Relate the image distance (v), object distance (u) , image height (h′) and object height (h) to the formula of magnification (M) for a mirror.

The correct option is C M=h′h = −vu M=h′h = −vu where h' is the image height, h is the object height, v is the image distance and u is the object distance.

Relate the image distance ( $v$ ), object distance ( $u$ ) , image height ( $h^{^{'}}$ ) and object height ( $h$ ) to the formula of magnification $(M)$ for a mirror.

The correct option is C
$M = \frac{h^{'}}{h}$ = $\frac{- v}{u}$

$M = \frac{h^{'}}{h}$ = $\frac{- v}{u}$ where h' is the image height, h is the object height, v is the image distance and u is the object distance.