Relate the image distance ( $v$ ), object distance ( $u$ ) , image height ( $h^{^{'}}$ ) and object height ( $h$ ) to the formula of magnification $(M)$ for a mirror.

$M = \frac{h}{h^{'}} = \frac{v}{u}$

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$M = \frac{h^{'}}{h} = \frac{- u}{v}$

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$M = \frac{h^{'}}{h} = \frac{- v}{u}$

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$M = \frac{h^{'}}{h} = \frac{u}{v}$

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Solution

The correct option is C
$M = \frac{h^{'}}{h} = \frac{- v}{u}$

$M = \frac{h^{'}}{h} = \frac{- v}{u}$ where h' is the image height, h is the object height, v is the image distance and u is the object distance.

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Similar questions

Relate the image distance ( $v$ ), object distance ( $u$ ) , image height ( $h^{^{'}}$ ) and object height ( $h$ ) to the formula of magnification $(M)$ for a mirror.

Relate the image distance (v), object distance(u) , image height(h') and object height(h) for the formula of magnification (M).

Q. Write down a formula for the magnification produced by a concave mirror.

(a) in terms of height of object and height of image
(b) in terms of object distance and image distance

Q. Calculate distance of an object from height

^{'} h^{'}

of a concave mirror of focal length

= 10

so as to obtain real image of magnification.

m = - 2, v = 2 u

What is the formula for linear magnification for lens?

v = Image distance

u = Object distance

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Relate the image distance (v), object distance (u) , image height (h′) and object height (h) to the formula of magnification (M) for a mirror.

The correct option is C M=h′h=−vu M=h′h=−vu where h' is the image height, h is the object height, v is the image distance and u is the object distance.

Relate the image distance ( $v$ ), object distance ( $u$ ) , image height ( $h^{^{'}}$ ) and object height ( $h$ ) to the formula of magnification $(M)$ for a mirror.

The correct option is C
$M = \frac{h^{'}}{h} = \frac{- v}{u}$

$M = \frac{h^{'}}{h} = \frac{- v}{u}$ where h' is the image height, h is the object height, v is the image distance and u is the object distance.