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Question

Relation between Exradius ,semiperimeter and circumradius can be given by
(r1 is the radius of the circle opposite the angle A)

A
r1=2Δsa,r1=4RcosA2sinB2sinC2
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B
r1=Δsa,r1=4RsinA2cosB2cosC2
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C
r1=2Δ(sa)(sb),r1=4RcosA2sinB2sinC2
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D
r1=Δ(sa)(sb)(sc),r1=4RcosA2sinB2sinC2
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