relation between internal resistance and external resistance across a cell

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$L e t a c e l l o f e m f E h a v i n g i n t e r n a l r e s i s \tan c e r i s c o n n e c t e d t o a n e x t e r n a l r e s i s \tan c e R i n a n e l e c t r i c c i r c u i t, s o, E = I (R + r), w h e r e I i s t h e c u r r e n t t h a t p a s s e s t h r o u g h t h e c e l l c i r c u i t w h e n c i r c u i t i s c l o s e d . S o t h e r e l a t i o n b e t w e e n R a n d r i s, r = (\frac{E}{I} - R)$

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relation between internal resistance and external resistance across a cell

Let a cell of emf E having internal resistance ris connected to an external resistance R in an electric circuit, so, E = IR+r, where I is the current that passes through the cell circuit when circuit is closed.So the relation between R and r is,r = EI-R