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Limiting Reagent or Reactant

Relation betw...

Question

Relation between $r_{1}$ and $r_{2}$ is:

A

r_{2} > r_{1}

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B

r_{2} = r_{1}

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C

r_{1} > r_{2}

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D

r_{1} << r_{2}

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Solution

The correct option is B $r_{2} = r_{1}$
The rate of reaction do not depends on the length of the carbon chain of the reactant.

So both the reactions are completed in same time.

So the rate of reactions of both the reactions are same.

That is $r_{1} = r_{2}$ .

Hence option $B$ is correct.

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Similar questions

Q. For the following reactions, the correct reaction rates

r_{1}, r_{2}, r_{1}^{'}

r_{2}^{'}

Let $c_{1} & c_{2}$ be the centers and $r_{1} & r_{2}$ be the radius of two circles. Then

Cases Conditions

p. 1. $| r_{1} - r_{2} | < c_{1} c_{2} < r_{1} + r_{2}$

q. 2. $| r_{1} - r_{2} | = c_{1} c_{2}$

r. 3. $c_{1} c_{2} < | r_{1} + r_{2} |$

s.

4. $r_{1} + r_{2} < c_{1} r_{2}$

t. 5. $r_{1} + r_{2} = c_{1} r_{2}$

R_{1}

R_{2}

be two relations defined on a non empty set A. Which of the following statements is false? Give reasons in support of your answer.
(a) If

R_{1}

R_{2}

are reflexive, then so is

R_{1} \cap R_{2}

R_{1}

R_{2}

are symmetric, then so is

R_{1} \cup R_{2}

R_{1}

R_{2}

are transitive, then so is

R_{1} \cup R_{2}

R_{1}

R_{2}

are transitive, then so is

R_{1} \cap R_{2}

R_{1}

R_{2}

are symmetric, then so is

R_{1} \cap R_{2}

R_{1} - C \equiv N + R_{2} M g B r (i) D r y e t h e r - ------ \to (i i) H_{3} O^{+} 1 - p h e n y l - 1 - p r o p a n o n e

R_{1}

R_{2}

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R_{1}

R_{2}

be two relations defined as follows:

R_{1} = {(a, b) \in R^{2} : a^{2} + b^{2} \in Q}

R_{2} = {(a, b) \in R^{2} : a^{2} + b^{2} \notin Q} .

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