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Critical Angle

Relationship ...

Question

Relationship between critical angle and refractive index.

A

\frac{1}{sin i_{c}} = μ

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B

sin i_{c} = μ

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C

sin i_{c} \times \frac{1}{μ}

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D

All

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Solution

The correct option is A $\frac{1}{sin i_{c}} = μ$
$_{a} μ_{g} = \frac{1}{s i n (i_{c})} = c o s e c (i_{c})$

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