Relative Density of silver is 10.5. The density of silver in SI unit is

105 Kg $m^{- 3}$

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1050 Kg $m^{- 3}$

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10500 Kg $m^{- 3}$

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10.5 Kg $m^{- 3}$

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Solution

The correct option is C. 10500 Kg $m^{- 3}$
Relative Density of silver is 10.5.
$Relative density = \frac{Density of silver}{Density of water at 4 degree celsius}$

$10.5 = \frac{Density of silver}{1000}$

Density of silver = 10500 Kg $m^{- 3}$ .

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