Question

Relative density of silver is $10.8$. Its density in $g/c{m}^3$ is

• A. $10.8$
• B. $5.6$
• C. $10$
• D. $13.8$

Answer 1

The correct option is A $10.8$

$R.D=\frac{\text{Density of object}}{\text{Density of water}}$
Here, Density of water $=1g/c{m}^3$
So, $R.D=\frac{\text{Density of silver}}{\text{Density of water}}$
$\text{Density of silver}=R.D\times \text{Density of water}=10.8$ x$1=10.8g/c{m}^3$