Relative Lowering of vapour pressure is highest in aqueous solution for:

0.1 M Urea

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.1 M Glucose

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.1 M M g S O_{4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.1 M B a C l_{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $0.1 M B a C l_{2}$
We know that, relative lowering of vapour pressure can be expressed by formula,
$\frac{P^{o} - P_{s}}{P^{o}} = i \times X_{s o l u t e}$
$\Rightarrow \frac{P^{o} - P_{s}}{P^{o}} \propto i$
(a) Urea is a non-electrolyte. It does not dissociate into its ions in aqueous solution. Hence, $i = 1$ .
(b) Glucose is a non-electrolyte. It does not dissociate into its ions in aqueous solution. Hence, $i = 1$ .
(c) $M g S O_{4}$ dissociate as $M g^{2 +}$ and $S O_{4}^{2 -}$ . Hence, $i = 2$ .
(d) $B a C l_{2}$ dissociate as $B a^{2 +}$ and $2 C l^{-}$ . Hence, $i = 3$ .

Suggest Corrections

Similar questions

Q. What is the relative lowering in vapour pressure of 10% aqueous solution of glucose :

An aqueous solution of glucose was prepared by dissolving 18g in 90g of water. The relative lowering of vapour pressure is

Q. The relative lowering of vapour pressure of an aqueous solution containing a non volatile solute is

0.0125

. The molality of the solution is:

Relative lowering of vapour pressure of a dilute aqueous solution of glucose is found to be $0.018$ . Hence, elevation in boiling point is:
(Given, that $1$ molal aqueous urea solution boils at $00.54^{o} C$ at $1$ atm pressure)

An aqueous solution of glucose was prepared by dissolving 18g in 90g of water. The relative lowering of vapour pressure is

Join BYJU'S Learning Program