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Question


Relative stabilities of the following structures of CH2=CH−CHO are in this decreasing order:

632272_b7b805b635d240cd93a7e93dd4b9cfaf.png

A
II > I > III
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B
I > II > III
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C
III > II > I
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D
I > III > II
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Solution

The correct option is B I > II > III
The decreasing order for the relative stabilities is I>II>III

In structure I, no charge separation is present. Hence, it is most stable.

In II, negative charge is on more electronegative O atom.

Hence, it is more stable than III, in which negative charge is on C atom.

Option B is correct.

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