CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Remove the second term from the equation:
x612x5+3x217x+300=0.

Open in App
Solution

f(x)=x612x5+3x217x+300=0

There are 6 roots of the equation and sum of the roots is 12, hence to eliminate the 2nd term we need to the reduce sum to zero.

Hence, we need to decrease each of the roots of the f(x)=0 by 2

Transform the equation by inputting x=x+2

(x+2)612(x+2)5+3(x+2)217(x+2)+300=0

x660x4320x3717x2773x42=0


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Relation of Roots and Coefficients
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon