Question

Repeat your calculation for a proton having the same velocity.

Answer 1

The force on a moving charged particle with velocity $\overrightarrow{v}$ placed in magnetic field $\overrightarrow{B}$ is given by

$\overrightarrow{F}=q(\overrightarrow{v}\times \overrightarrow{B})$

$q_{proton}=1.6\times {10}^{-19}C$

$=(1.6\times {10}^{-19}C)\left(\right[(2\times {10}^{6}m/s)\hat{i})+(3\times {10}^{6}m/s\left)\hat{j}\right]\times \left[\right(0.0303T)\hat{i}-(0.15T\left)\hat{j}\right])$

$=6.24\times {10}^{-14}N\hat{k}$