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Question

# Repeated observations in an experiment gave the values 1.29, 1.33, 1.34, 1.35, 1.32,1.36, 1.30 and 1.33. Find the relative error.

A

± 0.025

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B

± 0

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C

± 0.0175

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D

± 0.015

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Solution

## The correct option is D ± 0.015 Mean = 1.29+1.33+1.34+1.35+1.32+1.36+1.30.1.338 = 1.3275 = 1.33 (Rounding off to 3 digits) Sl.No.Observetionchange in xchange in x211.290.040.001621.330.000.00031.34−0.010.000141.35−0.020.000451.320.010.000161.36−0.030.000971.300.030.000981.330.000.0000 σ=√∑Δx2n=√0.0048 = 0.022 = 0.02 Absolute error = 0.02 Relative error = 0.021.33=±0.015

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