Dear Student,
Let a be placed in the blank.
Sum of the digits at odd places = 4 + 9 + 0 + 7 = 20
Sum of the digits at even places = 3 + a + 8 = 11 + a
Difference = 11 + a − 20 = a - 9
For a number to be divisible by 11, this difference should be zero or a multiple of 11.
If a - 9 = 0, then
a = 9
or
A closest multiple of 11, which is near to 9, has to be taken. It is 11 itself.
a - 9 = 11
a = 20
However it cannot be a two digit
Therefore, the required digit is 9.
Regards