Replace * by a suitable digit so that the number 5 * 9397 is divisible by 11
7
1
8
2
As 5 + 9 + 9 = 23 & * + 3 + 7 = 10 + * <br><br>23 - (10 + *) = 13 - * (should be o or a multiple of 11) so * = 2
Replace * by the smallest digit so that the number 56 * 891 is divisible by 3
Replace * by the smallest number, so that the number 1*1 is divisible by 3.
Given that the sum of digits of a 5 digit number is 41. Find the probability that such a number is divisible by 11?