Replace * by the smallest digit so that the number 56 * 891 is divisible by 3
The correct option is D 1
A number is completely divisible by 3 if the sum of its digits is divisible by 3.
Given number 56∗891.
Let the unknow digit be x
⇒5+6+x+8+9+1=29+x
So, smallest value of x such 29+x is divisible by 3 is 1.
Therefore, the required digit is 1 such that the given number is divisible by 3.