Draw a line l and mark zero on it
133=413=4+13 and
−133=−(4+13)
Therefore, from
O mark
OA,AB,BC,CD and
DE to the right of O such that,
OA=AB=BC=CD=DE=1 unit.
Clearly,
Point
A,B,C,D,E represents the Rational numbers
1,2,3,4,5 respectively.
Since, we have to consider
4 complete units and a part of the fifth unit, therefore divide the fifth unit
DE into
3 equal parts. Take
1 part out of these
3 parts. Then point
P is the representation of number
133 on the number line. Similarly, take
4 full unit lengths to the left of
0 and divide the fifth unit
D′E′ into
3 equal parts. Take
1 part out of these three equal parts. Thus,
P′ represents the rational number
−133