Question

Represent $\sqrt{3.5},\sqrt{4.3}\text{and}\sqrt{8.47}$ on number line.

Answer 1

Representing $\sqrt{3.5}$ on the number line

Draw a ray $AX$.

Mark a point on the ray such that $AP=3.5units$. From a point $P$, mark a point $Q$ such that $PQ=1unit$.

Draw perpendicular bisector of $AQ$ such that $O$ is the mid-point.

Taking $O$ as centre and $OQ$ as radius, draw a semicircle.

Draw $PR\perp AX$, intersecting the semi-circle at $R$.

With $P$ as centre and $PR$ as radius, draw an arc intersecting $AX$ at $S$.

Hence, $PS=PR=\sqrt{3.5}$

Representing $\sqrt{4.3}$ on the number line

Draw a ray $AX$.

Mark a point on the ray such that $AP=4.3units$. From a point $P$, mark a point $Q$ such that $PQ=1unit$.

Draw perpendicular bisector of $AQ$ such that $O$ is the mid-point.

Taking $O$ as centre and $OQ$ as radius, draw a semicircle.

Draw $PR\perp AX$, intersecting the semi-circle at $R$.

With $P$ as centre and $PR$ as radius, draw an arc intersecting $AX$ at $S$.

Hence, $PS=PR=\sqrt{4.3}$

Representing $\sqrt{8.47}$ on the number line

Draw a ray $AX$.

Mark a point on the ray such that $AP=8.47units$. From a point $P$, mark a point $Q$ such that $PQ=1unit$.

Draw perpendicular bisector of $AQ$ such that $O$ is the mid-point.

Taking $O$ as centre and $OQ$ as radius, draw a semicircle.

Draw $PR\perp AX$, intersecting the semi-circle at $R$.

With $P$ as centre and $PR$ as radius, draw an arc intersecting $AX$ at $S$.

Hence, $PS=PR=\sqrt{8.47}$