Question

Represent the complex number $Z=-2-\sqrt{2i}$ in the polar form

Answer 1

Given,

$z=-2-i\sqrt{2}$

$r=\sqrt{(-2{)}^2+(-\sqrt{2}{)}^2}=\sqrt{6}$

$\theta ={\tan }^{-1}\left(\frac{-\sqrt{2}}{-2}\right)=35.26$

$z=r{e}^{i\theta }=\sqrt{6}{e}^{i35.26}$