Represent the given sets in roster form $A_{2}$ = { $x$ : $x^{2} - 4 x - 5 = 0}$

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Solution

The set will have the elements as the solutions of $x^{2} - 4 x - 5 = 0$
$\Rightarrow x^{2} - 5 x + x - 5 = 0$
$\Rightarrow x (x - 5) + 1 (x - 5) = 0$
$\Rightarrow (x - 5) (x + 1) = 0$
$\Rightarrow x - 5 = 0$ (Or) $x + 1 = 0$
$\Rightarrow x = 5, - 1$
Now, Roster form of a set means, the set can be represent with the elements.
So, the roster form set is ${5, - 1}$

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