Resham wanted to save at least Rs.6500 for sending her daughter to school next year (after 12 months). She saved Rs.450 in the first month and raised her savings by Rs.20 every next month. How much will she be able to save in next 12 months ? Will she be able to send her daughter to the school next year?

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Solution

A= 450
d= 20
she have to save 6500
n=12
$S_{12} = \frac{12}{2} (2 \times 450 + (12 - 1) 20)$
$S_{12} = 6 \times (900 + 220)$
=6(1120)
= 6720
she saved rs 6720 in 12 months .
Yes, She will be able to send her daughter to school next year.

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A= 450 d= 20 she have to save 6500 n=12 S12=122(2×450+(12−1)20) S12=6×(900+220) =6(1120) = 6720 she saved rs 6720 in 12 months . Yes, She will be able to send her daughter to school next year.

A= 450
d= 20
she have to save 6500
n=12
$S_{12} = \frac{12}{2} (2 \times 450 + (12 - 1) 20)$
$S_{12} = 6 \times (900 + 220)$
=6(1120)
= 6720
she saved rs 6720 in 12 months .
Yes, She will be able to send her daughter to school next year.