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Ohm's Law in Scalar Form

Resistance of...

Question

Resistance of $1, 2$ and $3 o h m$ are connected in the form of a triangle . if a $1.5$ volt cell of negligible internal resistance is connected across the $3 o h m$ resistance, the current flowing through this resistance will be:

0.25

ampere

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0.5

ampere

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1.0

ampere

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1.5

ampere

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Solution

The correct option is B $0.5$ ampere
Applying kirchoff law:
$i_{1} + i_{2} = \frac{1.5}{3 / 2} = 1 a m p$
and according to question:

$\frac{i_{1}}{i_{2}} = \frac{3}{3} \Rightarrow i_{1} = i_{2}$

$∴ i_{2} = 0.5 A = i_{1}$

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Resistance of 1,2 and 3 ohm are connected in the form of a triangle . if a 1.5 volt cell of negligible internal resistance is connected across the 3 ohm resistance, the current flowing through this resistance will be:

The correct option is B 0.5 ampereApplying kirchoff law:i1+i2=1.53/2=1ampand according to question:i1i2=33⇒i1=i2∴i2=0.5A=i1

Resistance of $1, 2$ and $3 o h m$ are connected in the form of a triangle . if a $1.5$ volt cell of negligible internal resistance is connected across the $3 o h m$ resistance, the current flowing through this resistance will be:

The correct option is B $0.5$ ampere
Applying kirchoff law:
$i_{1} + i_{2} = \frac{1.5}{3 / 2} = 1 a m p$
and according to question:

$\frac{i_{1}}{i_{2}} = \frac{3}{3} \Rightarrow i_{1} = i_{2}$

$∴ i_{2} = 0.5 A = i_{1}$