Question

Resistance of $2\Omega$ and $3\Omega$ are connected in series. If the potential difference across the $2\Omega$ resistor is $3V$, the potential difference across $3\Omega$ is:

• A. $4.5V$
• B. $9V$
• C. $3V$
• D. $2V$

Answer 1

Answer: (A)

$4.5V$

$PD=3=IR=I\times 2$ , so current in the circuit is

$I=\frac{3}{2}=1.5A$

PD across $3\Omega$ is $PD=I\times R=1.5\times 3=4.5V$