Resistance of a wire at temperature t - C is R - R 01- at - bt 2Here- R 0 is the temperature at 0- C- The temperature coefficient of resistance at temperature t isA- a-2 b tB- a-1-n tC- 1-a t-b t2-a-2 b tD- constant

The correct option is B a+2bt/1+at+bt^2α =1/R.dR/dt=1/R_0(1+at+bt^2)[R_0(a+2bt)] = ( a+2bt/1+at+bt^2 ) ...

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Standard XII

Physics

Conductivity and Resistivity

Resistance of...

Question

Resistance of a wire at temperature $t^{\circ} C$ is
$R = R_{0} (1 + a t + b t^{2})$
Here, $R_{0}$ is the temperature at $0^{\circ} C$ . The temperature coefficient of resistance at temperature t is

\frac{a + 2 b t}{1 + a t + b t^{2}}

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(a + 2 b t)

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\frac{1 + a t + b t^{2}}{a + 2 b t}

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c o n s t a n t

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Solution

The correct option is A $\frac{a + 2 b t}{1 + a t + b t^{2}}$
$α = \frac{1}{R} . \frac{d R}{d t} = \frac{1}{R_{0} (1 + a t + b t^{2})} [R_{0} (a + 2 b t)]$
$= (\frac{a + 2 b t}{1 + a t + b t^{2}})$

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Similar questions

Q. Resistance of a resistor at temperature

t^{\circ} C

R_{t} = R_{0} (1 + a t + b t^{2})

; where

R_{0}

is the resistance at

0^{\circ} C .

The temperature coefficient of resistance at temperature

t^{\circ} C

Q. Resistance of a resistor at temperature

t

^{o} C

R_{t} = R_{0} (1 + α t + β t^{2})

, where

R_{0}

is the resistance at

0^{o} C

. The temperature coefficient of resistance at temperature

t^{o} C

Q. The temperature coefficient of resistance of a conductor varies as

α (T) = 3 T^{2} + 2 T

. If

R_{0}

is resistance at

T = 0

and

R

be resistance at

T

then

Q. The resistance of resistor at temperature

t^{o} C

can be expressed as

R_{t} = R_{0} (1 + 2 γ t + ϕ t^{2})

, where

R_{0}

is the resistance at

0^{o} C

and

γ

ϕ

are constants. The temperature coefficient of the resistance at

t^{o} C

Q. The resistance of resistor at temperature

t^{o} C

can be expressed as

R_{t} = R_{0} (1 + 2 γ t + ϕ t^{2})

, where

R_{0}

is the resistance at

0^{o} C

and

γ

ϕ

are constants. The temperature coefficient of the resistance at

t^{o} C

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Resistance of a wire at temperature t∘C is R=R0(1+at+bt2) Here, R0 is the temperature at 0∘C. The temperature coefficient of resistance at temperature t is

The correct option is A a+2bt1+at+bt2α=1R.dRdt=1R0(1+at+bt2)[R0(a+2bt)] =(a+2bt1+at+bt2)

Resistance of a wire at temperature $t^{\circ} C$ is
$R = R_{0} (1 + a t + b t^{2})$
Here, $R_{0}$ is the temperature at $0^{\circ} C$ . The temperature coefficient of resistance at temperature t is

The correct option is A $\frac{a + 2 b t}{1 + a t + b t^{2}}$
$α = \frac{1}{R} . \frac{d R}{d t} = \frac{1}{R_{0} (1 + a t + b t^{2})} [R_{0} (a + 2 b t)]$
$= (\frac{a + 2 b t}{1 + a t + b t^{2}})$