Question

Resistor $R_1$ and $R_2$ have an equivalent resistance of $6\Omega$ when connected in the circuit shown. The resistance of $R_1$ could be (in $\Omega$) $(R_1<R_2)$

• A. $1$
• B. $5$
• C. $8$
• D. $4$

Answer 1

The correct option is C $8$

• Two resistors when connected in parallel always have equivalent resistance less than or equal to the resistance of the smaller resistor. ${\frac{1}{R}}_{eq}={\frac{1}{R}}_1+{\frac{1}{R}}_2$
• Since the smaller resistance is $6\Omega$ ,the resistance of $R_1$ has to be greater than or equal to $6\Omega$.
  

Hence, the resistance of $R_1$ could be $8\Omega$