Resistors R1=10Ω, R2 = 40Ω, R3 = 30Ω, R4 = 20Ω, R5 = 60Ω and a 12V battery is connected as shown.
Calculate:
(a) the total resistance
(b) the total current flowing in the circuit. [3 MARKS]
Problem: 2 Marks
The situation is shown in (figure)
For R1 and R2 in parallel
1Rp1=1R1+1R2=110+140=540=18
or Rp1=8Ω
For R3,R4 and R5 is parallel
Rp2=10Ω
(a) For Rp1 and Rp2 in series.
Total resistance, R=Rp1+Rp2
Putting values, we get, R = 8 + 10 = 18
Total resistance, R = 18 Ω.
(b) From relation, (Ohm's law) R=VI
We have, I=VR
Putting values, we get, I = 0.67
Total current, I = 0.67 A