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Question

Resolve each of the following quadratic trinomial into factor:
14x2 + 11xy − 15y2

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Solution

The given expression is 14x2+11xy-15y2. (Coefficient of x2=14, coefficient of x=11y and constant term=-15y2)Now, we will split the coefficient of x into two parts such that their sum is 11y and their product equals the product of the coefficient of x2 and the constant term, i.e., 14×(-15y2)=-210y2.Now,21y+(-10y)=11y and21y×(-10y)=-210y2Replacing the middle term -11xy by -10xy+21xy, we get:14x2+11xy-15y2= 14x2-10xy+21xy-15y2 =(14x2-10xy)+(21xy-15y2) =2x(7x-5y)+3y(7x-5y) =(2x+3y)(7x-5y)

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