Resolve in to factors: $(1.6) a^{2} - (0.8) a$

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Solution

Given that : $(1.6) a^{2} - (0.8) a$
$= (0.8 \cdot 2) (a \cdot a) - (0.8) a$ , factor each monomial
$= (0.8 a) (2 a) - (0.8 a)$
$= 0.8 a (2 a - 1)$ , factor out common factor $(0.8) a$
Factors of $(1.6) a^{2} - (0.8) a$ are $0.8 a, (2 a - 1)$

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