Resolve into factors of $4 x^{2} - 25 y^{2} + 2 x + 5 y$

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Solution

$(2 x)^{2} - (5 y)^{2} + 2 x + 5 y$
$= (2 x - 5 y) (2 x + 5 y) + 1 (2 x + 5 y)$
$= (2 x + 5 y) (2 x - 5 y + 1)$

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State True or False

(−2x+5y−3z)² = 4x²+25y²+9z²−20xy−30yz+12zx

4 x^{2} + 5 y = 6 + 20 x y - 25 y^{2} + 2 x, 7 x - 11 y = 17

4 x^{2} + 5 y = 6 + 20 x y - 25 y^{2} + 2 x

7 x - 11 y = 17

4 x^{2} - 25 y^{2} + 30 y - 9

2 x + 5 y - 3

m^{2}

2 x^{2} + m x y + 3 y^{2} - 5 y - 2

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