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Question

Resolve into factors the expression (a+b+c)3a3b3c3

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Solution

The given expression becomes 0 when either a+b=0orb+c=0orc+a=0
and hence all these are its factors of 3rd degree.
Now assume (a+b+c)3a3b3c3=λ(a+b)(b+c)(c+a)
Choose a=0,b=1,c=2,
we get λ=3.

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