Resolve into factors the expression (a+b+c)3−a3−b3−c3
Open in App
Solution
The given expression becomes 0 when either a+b=0orb+c=0orc+a=0 and hence all these are its factors of 3rd degree. Now assume (a+b+c)3−a3−b3−c3=λ(a+b)(b+c)(c+a) Choose a=0,b=1,c=2, we get λ=3.