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Question

Resolve the following into factors:
(a)3a,b,c(a3)a,b,c

A
3(a+b)(b+c)(c+a)
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B
3(a+b)(b+c)(c+a)
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C
3(ab)(b+c)(ca)
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D
None
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Solution

The correct option is A 3(a+b)(b+c)(c+a)
Cyclic expressions refers to substitution of variables in cyclic manner.
We have, (a,b,ca)3(a,b,ca3)
=(a+b+c)3(a3+b3+c3)
=[a3+b3+c3+3(a+b)(b+c)(c+a)](a3+b3+c3)[(x+y+z)3=x3+y3+z3+3(x+y)(y+z)(z+x)]
=3(a+b)(b+c)(c+a)
So, A is the correct option.

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