wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Resolve the following into factors:
(a)3a,b,c(a3)a,b,c

A
3(a+b)(b+c)(c+a)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
3(a+b)(b+c)(c+a)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
3(ab)(b+c)(ca)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
None
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 3(a+b)(b+c)(c+a)
Cyclic expressions refers to substitution of variables in cyclic manner.
We have, (a,b,ca)3(a,b,ca3)
=(a+b+c)3(a3+b3+c3)
=[a3+b3+c3+3(a+b)(b+c)(c+a)](a3+b3+c3)[(x+y+z)3=x3+y3+z3+3(x+y)(y+z)(z+x)]
=3(a+b)(b+c)(c+a)
So, A is the correct option.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Multiplication of Algebraic Expressions
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon