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Question

Resolve the following quadratic trinomial into factors:
3+23y8y2

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Solution

Given: 3+23y8y2
=8y2+23y+3
On splitting the middle term , we get
=8y2+24yy+3
=8y(y3)1(y3)
=(8y1)(y3)
=(8y+1)(y3)
=(8y+1)(y+3)
=(8y+1)(3y)

Hence, 3+23y8y2=(8y+1)(3y)

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